embedded
assertion_error
ai_generated
true
FreeRTOS: xSemaphoreTakeRecursive failed on mutex 0x2000A000, mutex already taken by same task
ID: embedded/freertos-mutex-recursive-take
90%Fix Rate
89%Confidence
1Evidence
2024-11-01First Seen
Version Compatibility
| Version | Status | Introduced | Deprecated | Notes |
|---|---|---|---|---|
| FreeRTOS v10.5.1 | active | — | — | — |
| ARM GCC v12.2.1 | active | — | — | — |
Root Cause
A recursive mutex was taken by a task that already holds it without a corresponding recursive give, exhausting the nesting count.
generic中文
一个递归互斥锁被已持有它的任务获取,而没有相应的递归释放,耗尽了嵌套计数。
Official Documentation
https://www.freertos.org/a00122.htmlWorkarounds
-
95% success Ensure every xSemaphoreTakeRecursive is paired with an equal number of xSemaphoreGiveRecursive calls. Use a debug macro to track nesting count.
Ensure every xSemaphoreTakeRecursive is paired with an equal number of xSemaphoreGiveRecursive calls. Use a debug macro to track nesting count.
-
85% success Refactor code to avoid recursive mutex acquisition by using a single entry point that acquires the mutex once and calls nested functions without re-acquiring.
Refactor code to avoid recursive mutex acquisition by using a single entry point that acquires the mutex once and calls nested functions without re-acquiring.
中文步骤
Ensure every xSemaphoreTakeRecursive is paired with an equal number of xSemaphoreGiveRecursive calls. Use a debug macro to track nesting count.
Refactor code to avoid recursive mutex acquisition by using a single entry point that acquires the mutex once and calls nested functions without re-acquiring.
Dead Ends
Common approaches that don't work:
-
Replace recursive mutex with a standard mutex
90% fail
A standard mutex will cause a deadlock if the same task tries to take it again, as it does not support recursive acquisition.
-
Increase the configMAX_RECURSIVE_MUTEX_DEPTH value
60% fail
The depth is limited by task stack and memory; increasing it may mask the underlying nesting bug, leading to stack overflow later.
-
Add a delay before taking the mutex again
80% fail
Does not resolve the logic error; the mutex is already held, so delay only wastes CPU cycles without fixing the nesting count.