go type_error ai_generated true

恐慌：向只接收通道发送数据

panic: send on receive-only channel

ID: go/channel-direction-mismatch

其他格式: JSON · Markdown 中文 · English
80%修复率
80%置信度
0证据数
2024-12-01首次发现

版本兼容性

版本状态引入弃用备注
1.18 active — — —
1.19 active — — —

根因分析

尝试向声明为只接收（<-chan）的通道发送数据，或在只发送（chan<-）通道上接收。这是编译时错误，但如果类型断言使用不当，可能在运行时发生。

English

Attempting to send on a channel that is declared as receive-only (<-chan), or receive on a send-only channel (chan<-). This is a compile-time error, but can occur if type assertions are used incorrectly at runtime.

generic

解决方案

  1. 98% 成功率 
    func producer(ch chan<- int) {
    ch <- 1
}

func consumer(ch <-chan int) {
    v := <-ch
    fmt.Println(v)
}

ch := make(chan int)
go producer(ch)
consumer(ch)
  2. 95% 成功率 
    ch := make(chan int)

go func(ch chan<- int) {
    ch <- 42
}(ch)

v := <-ch
fmt.Println(v)

无效尝试

常见但无效的做法:

  1. 100% 失败

    Type assertions cannot change channel direction; it's a static property.

  2. 100% 失败

    The program will panic or fail to compile.