# TypeError: view must be a callable or a list/tuple in the case of include(). Received: <class 'dict'>

- **ID:** `python/django-view-return-http-response`
- **Domain:** python
- **Category:** config_error
- **Verification:** ai_generated
- **Fix Rate:** 80%

## Root Cause

In urls.py, passing a dictionary to path() instead of a view function or include().

## Version Compatibility

| Version | Status | Introduced | Deprecated |
|---------|--------|------------|------------|
| 3.x | active | — | — |

## Workarounds

1. **** (95% success)
   ```
   Define a proper view function and pass it: path('url/', my_view)
   ```
2. **** (90% success)
   ```
   Use include() with a URLconf module.
   ```

## Dead Ends

- **** — Does not make sense; path() expects a callable. (90% fail)
- **** — May work but is not a clean solution; better to define a proper view. (60% fail)