python config_error ai_generated true

TypeError: 视图必须是可调用的或列表/元组（在include()的情况下）。收到：<class 'dict'>

TypeError: view must be a callable or a list/tuple in the case of include(). Received: <class 'dict'>

ID: python/django-view-return-http-response

其他格式: JSON · Markdown 中文 · English
80%修复率
84%置信度
0证据数
2024-11-08首次发现

版本兼容性

版本状态引入弃用备注
3.x active — — —

根因分析

在urls.py中，向path()传递字典而不是视图函数或include()。

English

In urls.py, passing a dictionary to path() instead of a view function or include().

generic

解决方案

  1. 95% 成功率 
    Define a proper view function and pass it: path('url/', my_view)
  2. 90% 成功率 
    Use include() with a URLconf module.

无效尝试

常见但无效的做法:

  1. 90% 失败

    Does not make sense; path() expects a callable.

  2. 60% 失败

    May work but is not a clean solution; better to define a proper view.