python config_error ai_generated true

ValueError: 'seaborn' is not a valid style sheet. Available styles: ['bmh', 'classic', 'dark_background', 'fast', 'fivethirtyeight', 'ggplot', 'grayscale', 'seaborn-v0_8', 'seaborn-v0_8-bright', 'seaborn-v0_8-colorblind', 'seaborn-v0_8-dark', 'seaborn-v0_8-dark-palette', 'seaborn-v0_8-darkgrid', 'seaborn-v0_8-deep', 'seaborn-v0_8-muted', 'seaborn-v0_8-notebook', 'seaborn-v0_8-paper', 'seaborn-v0_8-pastel', 'seaborn-v0_8-talk', 'seaborn-v0_8-ticks', 'seaborn-v0_8-white', 'seaborn-v0_8-whitegrid', 'tableau-colorblind10']

ID: python/matplotlib-seaborn-style-error

Also available as: JSON · Markdown · 中文
80%Fix Rate
87%Confidence
0Evidence
2024-05-01First Seen

Version Compatibility

VersionStatusIntroducedDeprecatedNotes
3.8 active
3.9 active

Root Cause

In matplotlib 3.6+, the 'seaborn' style was renamed to 'seaborn-v0_8' to avoid confusion with the seaborn library; using the old name raises an error.

generic

中文

在matplotlib 3.6+中,'seaborn'样式已重命名为'seaborn-v0_8',以避免与seaborn库混淆;使用旧名称会引发错误。

Workarounds

  1. 95% success Use the correct style name with version suffix
    plt.style.use('seaborn-v0_8-darkgrid')
  2. 90% success Use an alternative style like 'ggplot'
    plt.style.use('ggplot')

Dead Ends

Common approaches that don't work:

  1. Installing seaborn library to fix the style 90% fail

    The style is built into matplotlib; seaborn library is separate and not required for styles.

  2. Using 'seaborn-darkgrid' without the version suffix 85% fail

    All seaborn styles now require the 'seaborn-v0_8-' prefix.