python type_error ai_generated true

类型错误：skipIf() 参数 1 必须是布尔值，而不是字符串

TypeError: skipIf() argument 1 must be bool, not str

ID: python/unittest-skipif-condition-error

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80%修复率
87%置信度
0证据数
2024-06-18首次发现

版本兼容性

版本状态引入弃用备注
3.8 active — — —
3.9 active — — —

根因分析

@unittest.skipIf 装饰器接收了字符串条件而非布尔表达式，通常是由于缺少调用或语法错误。

English

The @unittest.skipIf decorator received a string condition instead of a boolean expression, often due to missing call or wrong syntax.

generic

解决方案

  1. 90% 成功率 Ensure the condition is a boolean expression, not a string. 
    @unittest.skipIf(sys.version_info < (3, 9), 'Requires Python 3.9+')
  2. 85% 成功率 Use skipUnless for inverse logic if condition is complex. 
    @unittest.skipUnless(hasattr(module, 'function'), 'Module missing function')

无效尝试

常见但无效的做法:

  1. Using skipIf with a string literal like 'True' 80% 失败

    String 'True' is not a boolean; it will always evaluate to True (truthy) but cause TypeError.

  2. Wrapping the condition in quotes to avoid syntax errors 75% 失败

    Quotes make it a string, which is not accepted by skipIf.