ros2 runtime_error ai_generated true

rclpy: 服务调用超时，等待来自/my_service的响应

rclpy: Service call timed out waiting for response from /my_service

ID: ros2/ros2-service-call-timeout-no-response

其他格式: JSON · Markdown 中文 · English
80%修复率
85%置信度
1证据数
2023-11-12首次发现

版本兼容性

版本状态引入弃用备注
ROS2 Humble (rclpy 3.3.0) active — — —
ROS2 Iron (rclpy 4.0.0) active — — —
ROS2 Rolling (rclpy 5.0.0) active — — —

根因分析

服务服务器在超时时间内没有响应，通常是因为它正忙、被阻塞或没有正确旋转。

English

The service server is not responding within the timeout period, often because it is busy, blocked, or not properly spinning.

generic

官方文档

https://docs.ros2.org/latest/api/rclpy/api/services.html

解决方案

  1. 检查服务器节点是否在旋转：确保服务器代码中调用了rclpy.spin(node)。如果使用多线程执行器，请验证它正在运行。
  2. 在客户端中添加带有指数退避的重试机制：while not future.done(): time.sleep(0.1); if not rclpy.ok(): break

无效尝试

常见但无效的做法:

  1. Increase the timeout duration in the client code 70% 失败

    The server may be completely unresponsive; a longer timeout just delays the failure.

  2. Restart the client node only 90% 失败

    The server node needs to be restarted or checked; client restart does not fix server issues.