E0308
rust
type_error
ai_generated
true
错误[E0308]: 类型不匹配 —— 期望 `impl Future<Output = ()>`,找到 `()`
error[E0308]: mismatched types -- expected `impl Future<Output = ()>`, found `()`
ID: rust/e0308-mismatched-types-async
90%修复率
85%置信度
1证据数
2023-08-12首次发现
版本兼容性
| 版本 | 状态 | 引入 | 弃用 | 备注 |
|---|---|---|---|---|
| 1.65.0 | active | — | — | — |
| 1.72.0 | active | — | — | — |
| 1.80.0 | active | — | — | — |
根因分析
异步函数或块直接返回了一个值,而不是返回一个 Future,通常是由于缺少 'async' 关键字或返回类型不正确。
English
An async function or block is returning a value directly instead of returning a Future, often due to missing 'async' keyword or incorrect return type.
官方文档
https://doc.rust-lang.org/stable/error_codes/E0308.html解决方案
-
Add 'async' keyword to the function definition: 'async fn my_func() -> () { /* ... */ }'. This wraps the return value in a Future. -
If the function must return a Future manually, change return type to 'Pin<Box<dyn Future<Output = ()>>>' and return 'Box::pin(async move { ... })'.
无效尝试
常见但无效的做法:
-
80% 失败
Adding '.await' at the call site without making the calling function async — this causes a different error about 'await' outside async context.
-
60% 失败
Returning a 'Box::pin(future)' without adjusting the return type — still mismatched type.