E0597 rust type_error ai_generated true

error[E0597]: borrowed value does not live long enough note: argument requires that `value` is borrowed for `'static`

ID: rust/e0597-borrowed-value-from-iterator

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87%Fix Rate
82%Confidence
1Evidence
2023-09-20First Seen

Version Compatibility

VersionStatusIntroducedDeprecatedNotes
rustc 1.76 active — — —
rustc 1.77 active — — —

Root Cause

Returning a reference to a local variable created inside a function or closure, often from an iterator chain like `.filter()` or `.map()`.

generic

中文

返回对在函数或闭包内部创建的局部变量的引用，通常来自迭代器链如 `.filter()` 或 `.map()`。

Official Documentation

https://doc.rust-lang.org/stable/error_codes/E0597.html

Workarounds

  1. 90% success Clone or own the data instead of borrowing: `let cloned = value.clone();` or collect into a `Vec` before returning. 
    Clone or own the data instead of borrowing: `let cloned = value.clone();` or collect into a `Vec` before returning.
  2. 85% success Restructure the code to pass ownership: change function signature to return an owned type like `String` instead of `&str`. 
    Restructure the code to pass ownership: change function signature to return an owned type like `String` instead of `&str`.

中文步骤

  1. 克隆或拥有数据而不是借用：`let cloned = value.clone();` 或在返回前收集到 `Vec` 中。
  2. 重构代码以传递所有权：将函数签名改为返回拥有类型如 `String` 而不是 `&str`。

Dead Ends

Common approaches that don't work:

  1. 80% fail

    The data still doesn't live long enough; the lifetime bound is a promise the compiler enforces, not a magic fix.

  2. 95% fail

    Can cause dangling pointers and undefined behavior; highly discouraged.