python type_error ai_generated true

TypeError: skipIf() argument 1 must be bool, not str

ID: python/unittest-skipif-condition-error

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80%Fix Rate
87%Confidence
0Evidence
2024-06-18First Seen

Version Compatibility

VersionStatusIntroducedDeprecatedNotes
3.8 active — — —
3.9 active — — —

Root Cause

The @unittest.skipIf decorator received a string condition instead of a boolean expression, often due to missing call or wrong syntax.

generic

中文

@unittest.skipIf 装饰器接收了字符串条件而非布尔表达式，通常是由于缺少调用或语法错误。

Workarounds

  1. 90% success Ensure the condition is a boolean expression, not a string. 
    @unittest.skipIf(sys.version_info < (3, 9), 'Requires Python 3.9+')
  2. 85% success Use skipUnless for inverse logic if condition is complex. 
    @unittest.skipUnless(hasattr(module, 'function'), 'Module missing function')

Dead Ends

Common approaches that don't work:

  1. Using skipIf with a string literal like 'True' 80% fail

    String 'True' is not a boolean; it will always evaluate to True (truthy) but cause TypeError.

  2. Wrapping the condition in quotes to avoid syntax errors 75% fail

    Quotes make it a string, which is not accepted by skipIf.