ros2 runtime_error ai_generated true

rclpy: Service call timed out waiting for response from /my_service

ID: ros2/ros2-service-call-timeout-no-response

Also available as: JSON · Markdown · 中文
80%Fix Rate
85%Confidence
1Evidence
2023-11-12First Seen

Version Compatibility

VersionStatusIntroducedDeprecatedNotes
ROS2 Humble (rclpy 3.3.0) active — — —
ROS2 Iron (rclpy 4.0.0) active — — —
ROS2 Rolling (rclpy 5.0.0) active — — —

Root Cause

The service server is not responding within the timeout period, often because it is busy, blocked, or not properly spinning.

generic

中文

服务服务器在超时时间内没有响应，通常是因为它正忙、被阻塞或没有正确旋转。

Official Documentation

https://docs.ros2.org/latest/api/rclpy/api/services.html

Workarounds

  1. 85% success Check that the server node is spinning: ensure rclpy.spin(node) is called in the server code. If using a multithreaded executor, verify it is running. 
    Check that the server node is spinning: ensure rclpy.spin(node) is called in the server code. If using a multithreaded executor, verify it is running.
  2. 80% success Add a retry mechanism with exponential backoff in the client: while not future.done(): time.sleep(0.1); if not rclpy.ok(): break 
    Add a retry mechanism with exponential backoff in the client: while not future.done(): time.sleep(0.1); if not rclpy.ok(): break

中文步骤

  1. 检查服务器节点是否在旋转：确保服务器代码中调用了rclpy.spin(node)。如果使用多线程执行器，请验证它正在运行。
  2. 在客户端中添加带有指数退避的重试机制：while not future.done(): time.sleep(0.1); if not rclpy.ok(): break

Dead Ends

Common approaches that don't work:

  1. Increase the timeout duration in the client code 70% fail

    The server may be completely unresponsive; a longer timeout just delays the failure.

  2. Restart the client node only 90% fail

    The server node needs to be restarted or checked; client restart does not fix server issues.