python config_error ai_generated true

TypeError: view must be a callable or a list/tuple in the case of include(). Received: <class 'dict'>

ID: python/django-view-return-http-response

Also available as: JSON · Markdown · 中文
80%Fix Rate
84%Confidence
0Evidence
2024-11-08First Seen

Version Compatibility

VersionStatusIntroducedDeprecatedNotes
3.x active — — —

Root Cause

In urls.py, passing a dictionary to path() instead of a view function or include().

generic

中文

在urls.py中，向path()传递字典而不是视图函数或include()。

Workarounds

  1. 95% success 
    Define a proper view function and pass it: path('url/', my_view)
  2. 90% success 
    Use include() with a URLconf module.

Dead Ends

Common approaches that don't work:

  1. 90% fail

    Does not make sense; path() expects a callable.

  2. 60% fail

    May work but is not a clean solution; better to define a proper view.